Physical Chemistry Third Edition

K Answers to Numerical Exercises and Odd-Numbered Numerical Problems 1345

Chapter 25 Problems

25.1
a. 10 states

b. p 0 

4

10

 0. 4

p 1 

3

10

 0. 3

p 2 

2

10

 0. 2

p 3 

1

10

 0. 1

c.p 0 

1

3

 0. 3333

p 1 

1

3

 0. 3333

p 2 

1

3

 0. 3333

p 3  0

25.3
a. There are 5 system states
b. Eachpv 0. 200
c.p 0  0. 250
p 1  0. 250
p 2  0
p 3  0. 250
p 4  0. 250

25.5
s 1. 1114

25.7
a. 2.02%
b. 0.00200%

25.9
V − 0 .00034 J
K 3718 J

25.11
x1,y 1
f 0 .1353 at the constrained maximum

25.13
xy 0. 65327
f 0 .39665 at the constrained maximum

25.15
a. z 8. 7701 × 1031

b. probability 2. 54 × 10 −^33

25.17

a. ratio 2. 836 × 10 −^5 at 298.15 K

b. ratio 1. 943 × 10 −^3 at 500 K

c. ratio 0 .04408 at 1000 K

d. ratio 0 .5356 at 5000 K

e. ratio→ 1

25.19

a. ratio 2 .9446 at 298.15 K

b. ratio 2 .9834 at 1000 K

c. ratio→ 3

25.21

a. zrot 180. 0

b. Jmp≈ 9

c. probability 0. 06402

25.23

ForV 0 .02500 m^3 ,z 6. 107 × 1030

ForV 1 .00 m^3 ,z 2. 443 × 1032

25.25

z 9. 92 × 1030

25.27

For helium,z 1. 911 × 1029

For krypton,z 1. 815 × 1031

25.29

At 300.0K,z 2. 71 × 1033

At 500.0K,z 1. 04 × 1034

25.31

zrot 1. 880

25.33

zrot 424. 8

25.35

fraction 0. 36788

25.37

zrot 36. 42

25.41

b. Ω 60

c. Ω 24

25.45

a. FALSE