6.3 Activity and Activity Coefficients 261
where we attach the superscript (I) to specify that we are using convention I.
Sinceμ
◦(I)
i is the chemical potential of the pure liquid,μ
∗
i, it is equal to the chem-
ical potential of the gaseous substance at a partial pressure equal to the equilibrium
vapor pressureP∗i:
μ∗iμ◦i(I)μ◦i(g)+RTln
(
Pi∗
P◦
)
(6.3-20)
We are ignoring a small correction inμ◦i(I)due to the fact that the standard state is
atPP◦1 bar, whereasμ∗i pertains to pressurePi∗. The relation of Eq. (6.3-19)
becomes
μ◦i(g)+RTln
(
Pi∗
P◦
)
+RTlna(I)i μ◦i(g)+RTln
(
Pi
P◦
)
(6.3-21)
Canceling equal terms and taking antilogarithms in Eq. (6.3-21), we obtain
PiPi∗a(I)i (6.3-22)
which resembles Raoult’s law except that the activitya
(I)
i occurs instead of the mole
reactionxi. The activity acts as an “effective” mole fraction in determining the partial
vapor pressure of the substance. Equation (6.3-22) is equivalent to
a(iI)
Pi
Pi∗
(6.3-23)
Theactivity coefficientin convention I is defined as the ratio of the activity to the
mole fraction:
γ(I)i
a(iI)
xi
(definition of the activity coefficient) (6.3-24)
It is equal to the actual vapor pressure divided by the value of the vapor pressure that
is predicted by Raoult’s law:
γi(I)
Pi/P◦
Pi,ideal/P◦
Pi
Pi∗xi
(6.3-25)
The activity coefficient specifies how the substance deviates from Raoult’s law. If
γi>1, the partial vapor pressure of substanceiis higher than predicted by Raoult’s
law, and ifγi<1, it is lower than predicted by Raoult’s law.
EXAMPLE6.11
Find the value of the activity and the activity coefficient of 2,2,4-trimethyl pentane (com-
ponent 2) in ethanol at 25◦C at a mole fraction of 0.2748, according to convention I. The
partial vapor pressure is equal to 48.31 torr and the vapor pressure of the pure liquid is equal
to 59.03 torr.