400 9 Gas Kinetic Theory: The Molecular Theory of Dilute Gases at Equilibrium
EXAMPLE 9.3
Show that the Gaussian distribution of Eq. (9.3-33) is normalized.
Solution
∫∞
−∞
f(u)du
1
√
2 πσ
∫∞
−∞
e−(u−μ)
(^2) / 2 σ 2
du
1
√
2 πσ
∫∞
−∞
e−w
(^2) / 2 σ 2
dw
1
√
2 πσ
√
2 σ
∫∞
−∞
e−t
2
dt
1
√
2 πσ
√
2 σ
√
π 1
where we have looked up the integral in Appendix C.
The Gaussian curve is named for
Johann Carl Friedrich Gauss,
1777–1855, a great German
mathematician who made many
fundamental contributions to
mathematics.
The standard deviation of an arbitrary probability distribution is defined by
σu
(〈
u^2
〉
−〈u〉^2
) 1 / 2
(definition ofσu) (9.3-34)
The standard deviation is a convenient measure of the width of a probability distribution.
For a Gaussian distribution the probability thatulies betweenμ−σandμ+σis equal
to 0.683. For most other probability distributions the probability that the independent
variable lies within one standard deviation of the mean is approximately equal to
two-thirds.
Exercise 9.7
a.Show that〈u〉μfor the Gaussian distribution of Eq. (9.3-33).
b.Show that the definition in Eq. (9.3-34) when applied to the Gaussian probability distribution
leads toσuσ.
By comparison of Eq. (9.3-32) and Eq. (9.3-33), the standard deviationσvxfor the
probability distribution ofvxis given by
σvx
√
kBT
m
√
RT
M
(9.3-35)
In the second equalityMis the molar mass. The value ofσvxfor O 2 molecules at 298 K
is equal to 278 m s−^1 , which is equal to 623 miles per hour.
The standard deviation of a functionh(u) is defined by
σh
[〈
h(u)^2
〉
−〈h(u)〉^2
] 1 / 2
(definition) (9.3-36)
EXAMPLE 9.4
Obtain a formula forσκx, the standard deviation of thevxcontribution to the kinetic energy,
κxmv^2 x/2.