11.3 Forward Reactions with More Than One Reactant 501
This is the same as
1
[A]t−
1
[A] 0
kfbt (11.3-8)where we drop the prime symbol (′)ont. Equation (11.3-8) is the same as Eq. (11.2-11)
except for the appearance of the factorbin the right-hand side.EXAMPLE11.8
Some of the damage to the ozone layer of the upper atmosphere might involve the reactionNO+O 3 −→NO 2 +O 2The reaction is first order in each reactant and the rate constant is equal to 1. 3 × 106 L
mol−^1 s−^1 at 298 K. If the initial concentrations of NO and O 3 are both equal to 1. 00 ×
10 −^6 mol L−^1 , find the concentrations of NO and O 3 at timet 2 .00 s.
Solution1
[NO]
1
NO 0
+kft
1
1. 00 × 10 −^6 mol L−^1+(1. 3 × 106 L mol−^1 s−^1 )(2.00 s) 3. 6 × 106 L mol−^1[NO][O 3 ]1
3. 6 × 106 L mol−^1 2. 8 × 10 −^7 mol L−^1Exercise 11.12
a.Find the half-life of the reaction in the previous example with the given initial concentrations.
b.Find the half-life of the reaction in the previous example with initial concentrations both
equal to 5. 00 × 10 −^5 mol L−^1.In the case that the reactants are not mixed in the stoichiometric ratio we separate
the variables in Eq. (11.3-6a):
1
([A] 0 −ax)([B] 0 −bx)dxkfdt (11.3-9)This equation can be integrated by the method ofpartial fractions. If we write
1
([A] 0 −ax)([B] 0 −bx)G
[A] 0 −ax+
H
[B] 0 −bx(11.3-10)
thenGandHare guaranteed by a theorem of algebra to be constants. These constants
are found to beG1
[B] 0 −b[A] 0 /aand H1
[A] 0 −a[B] 0 /bExercise 11.13
Verify the expressions forGandH.