13.1 Catalysis 581
b.The same reaction on nickel appears to follow the
Langmuir–Rideal mechanism. Write the rate law that
you would expect to find for this case.
13.2Apply the steady-state approximation to obtain a rate law
for the reaction A 2 −→products with the assumed
mechanism
( 1 ) A 2 +2 surface sites 2 A(adsorbed)
( 2 ) A(adsorbed) −→further intermediates or products
What condition would make this rate law coincide with
that obtained with the quasi-equilibrium approximation?
13.3 a.Derive the rate law for the reaction of a substance A
that undergoes a unimolecular reaction on a catalytic
surface in the case that a nonreacting substance C also
adsorbs on the surface. Assume that each substance
obeys the Langmuir isotherm.
b.In the case that C adsorbs more strongly than A, the
catalyst can bepoisonedby C. Poisoning can occur if
lead is adsorbed on the surface of the catalyst in an
automobile’s catalytic converter. Find the rate law if C
is much more strongly adsorbed than A.
13.4Assume that a diatomic reactant dissociates when it is
absorbed on a solid catalyst from the gas phase:
A 2 (g)+2 surface sites2 A(ads)
a.Find an expression forθ, the equilibrium fraction of
surface sites occupied as a function of [A 2 ], the
concentration of A 2 in the gas phase.
b.For the reaction A 2 +2B−→products assume the
Langmuir–Rideal mechanism, which means that a
B molecule in the gas phase collides with an adsorbed
A atom and reacts without being adsorbed itself:
(1) A 2 (g)+2 surface sites 2 A(ads)
(2) A(ads)+B(g)−→products
Write the rate law, assuming the second step to be the
rate-limiting step.
13.5 The following reaction is catalyzed by the bromide ion:
H++HNO 2 +φNH 2
Br−
−→φN+ 2 +2H 2 O
whereφrepresents the phenyl group. A proposed
mechanism is
(1) H++HNO 2 HNO+ 2
(2) H 2 NO+ 2 +Br−−→ONBr+H 2 O
(3) ONBr+φNH 2 −→φN+ 2 +H 2 O+Br−
a.Find the rate law, assuming the second step to be
rate-limiting.
b.Find the rate law, assuming the quasi-steady-state
approximation. What is the effect of assuming that the
third step is much faster than the second step?
13.6The decomposition of nitrous oxide, N 2 O, on a platinum
surface is apparently inhibited by the adsorption of the O 2
produced. For the case of zero initial partial pressure of
O 2 , the observed rate law is
−
dP(N 2 O)
dt
aP(N 2 O)
1 +(b/ 2 )[P 0 (N 2 O)−P(N 2 O)]
aP(N 2 O)
1 +bP(O 2 )
whereaandbare temperature-dependent parameters and
whereP 0 (N 2 O) is the initial pressure of N 2 O.
a.Assuming that both substances obey the Langmuir
isotherm, derive this rate law, stating any necessary
assumptions. Identify the parametersaandb.
b.Integrate the rate law to obtain
1 +bP 0
t
ln
(
P 0
P 0 −x
)
a+b
(x
t
)
whereP 0 P 0 (N 2 O)/2 and wherexP(O 2 ).
c.Following are data of Hinshelwood and Pritchard for
this reaction at 741◦C and forP 0 190 torr:
t/s 315 750 1400 2250 3450 5150
x/torr 10 20 30 40 50 60
Using a least-squares method, fit these data to the
integrated rate law and determine the values ofa
andb.
13.7The platinum-catalyzed oxidation of methanol apparently
proceeds through formation of formaldehyde and then
carbon monoxide.^16 The following mechanism is
proposed for the oxidation of the carbon monoxide:
(1) CO(g)+surface siteCO(adsorbed)
(2) O 2 +surface siteO 2 (adsorbed)
(3) O 2 (adsorbed)+surface site−→2O(adsorbed)
(4) CO(adsorbed)+O(adsorbed)−→CO 2 (g)
(^16) R. W. McCabe and D. F. McCready,J. Phys. Chem., 90 , 1428
(1986).