690 16 The Principles of Quantum Mechanics. II. The Postulates of Quantum Mechanics
The operator for|L|, the magnitude of the angular momentum, is not usable
since|L|(L^2 )^1 /^2 (L^2 x+L^2 y+L^2 z)^1 /^2 (16.3-15)and we have no procedure for unscrambling the square root when the operator is
formed. To obtain information about the magnitude of the angular momentum we will
use theL^2 operator.Exercise 16.3
a.Construct the operator forL̂x.
b.Construct the operator forL̂y.
c.Construct the operator forL^2 z(the square of the operator forLz).It is sometimes useful to have operator expressions for commutators.EXAMPLE16.4
Find the operator equal to the commutator[
̂x,p̂x]
.
Solution
Operate on an arbitrary differentiable functionf(x):[
̂x,̂px]
f ̄
h
i[
x
∂f
∂x
−
∂(xf)
∂x]
− ̄
h
i
fThe operator equation is
[
̂x,p̂x]
− ̄
h
i
ih ̄ (16.3-16)Equation (16.3-16) is an important result. Some authors find the form of the operator
̂pxby postulating that this commutation relation must hold.Exercise 16.4
a.Find the commutator [̂px,̂py].
b.Show that [
̂Lx,̂py]
ih ̄̂pz (16.3-17)If an operator is needed in another coordinate system, the operator is first constructed
in Cartesian coordinates and then transformed to the other coordinate system. For
example, if a particle moves in thexyplane, its position can be represented using the
polar coordinatesρandφ:ρ√
x^2 +y^2 (16.3-18)φarctan(y/x) (16.3-19)