Physical Chemistry Third Edition

(C. Jardin) #1

2.5 Enthalpy 75


The Heat Capacity at Constant Pressure


The heat capacity at constant pressure is given by

CP lim
∆T→ 0

( q
∆T

)

P,n

 lim
∆T→ 0

(

∆H

∆T

)

P,n



(

∂H

∂T

)

P,n

(2.5-8)

The heat capacity at constant pressure is the most commonly measured heat capacity
for solids and liquids. We now obtain an expression for the difference betweenCPand
CV. We begin with

CP

(

∂H

∂T

)

P,n



(

∂(U+PV)

∂T

)

P,n



(

∂U

∂T

)

P,n

+P

(

∂V

∂T

)

P,n

(2.5-9)

There is noV(∂P/∂T) term becausePis held constant in the differentiation. Equation
(B-7) of Appendix B gives, as an example of thevariable-change identity, the relation
(
∂U
∂T

)

P,n



(

∂U

∂T

)

V,n

+

(

∂U

∂V

)

T,n

(

∂V

∂T

)

P,n

(2.5-10)

We substitute this equation into Eq. (2.5-9) and use the fact thatCV(∂U/∂T)V,nto
write

CPCV+

((

∂U

∂V

)

T,n

+P

)(

∂V

∂T

)

P,n

(2.5-11)

For an ideal gas, (∂U/∂V)T,n0 and (∂V /∂T)P,nnR/P, so that

CPCV+nR (ideal gas) (2.5-12)

The physical explanation for this difference betweenCPandCVis that heating an
ideal gas at constant volume does not work on the surroundings. In heating at constant
pressure some of the heat is turned into work against the external pressure as the
gas expands. A larger amount of heat is therefore required for a given change in the
temperature than for a constant-volume process. In Chapter 4 we will be able to show
thatCPcannot be smaller thanCVfor any system.
Equations (2.3-10) through (2.3-12) together with Eq. (2.5-12) give the following
relations for dilute gases:

CP≈

5

2

nR (dilute monatomic gases) (2.5-13a)

CP≈

7

2

nR (dilute diatomic or linear polyatomic gases) (2.5-13b)

CP≈ 4 nR (dilute nonlinear polyatomic gases) (2.5-13c)
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