13 xyOAB1 xyOy =ln(x ) 2y=lnxyx(1 3),(3 1),
O
y=xy=ex-3
y=3+lnxLogarithms (Chapter 5) 151Example 27 Self Tutor
Consider the function f:x 7 !ex¡^3.
a Find the equation defining f¡^1.
b Sketch the graphs of f and f¡^1 on the same set of axes.
c State the domain and range of f and f¡^1.
d Find any asymptotes and intercepts of f and f¡^1.a f(x)=ex¡^3 b
) f¡^1 is x=ey¡^3
) y¡3=lnx
) y=3+lnx
So, f¡^1 (x)=3+lnxc Function f f¡^1
Domain x 2 R x> 0
Range y> 0 y 2 Rd For f, the horizontal asymptote is y=0,
and they-intercept ise¡^3.For f¡^1 , the vertical asymptote is x=0,
and thex-intercept ise¡^3.2 For the following functionsf:
i Find the equation of f¡^1.
ii Sketch the graphs of f and f¡^1 on the same set of axes.
iii State the domain and range of f and f¡^1.
iv Find any asymptotes and intercepts of f and f¡^1.a f(x)=ex+5 b f(x)=ex+1¡ 3
c f(x)=lnx¡ 4 , x> 0 d f(x) = ln(x¡1) + 2, x> 1
3 Consider the graphs A and B. One of them is the graph of
y=lnx and the other is the graph of y=ln(x¡2).
a Identify which is which. Give evidence for your answer.
b Copy the graphs onto a new set of axes and add to them
the graph of y=ln(x+2).
c Find the equation of the vertical asymptote for each graph.4 Kelly said that in order to graph y=ln(x^2 ),x> 0 , you
could first graph y=lnx and then double the distance
of each point on the graph from thex-axis.
Is Kelly correct? Explain your answer.4037 Cambridge
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Y:\HAESE\CAM4037\CamAdd_05\151CamAdd_05.cdr Friday, 20 December 2013 1:05:49 PM BRIAN