188 Straight line graphs (Chapter 7)Example 12 Self Tutor
Findyin terms ofx:
aba The graph ofyagainstx^3 is linear.
The gradient is
11 ¡ 5
3 ¡ 0
=2, and
they-intercept is 5.
) the equation is y=2x^3 +5.b The graph ofyagainstp
xis linear.) the equation is
y¡2=^34 (p
x¡4)
) y¡2=^34p
x¡ 3
) y=^34p
x¡ 1 , x> 0Example 13 Self Tutor
a Findyin terms ofx.
b Findywhen x=4.a) the equation is
y
x
¡4=
1
2
(x¡2))
y
x
¡4=
1
2
x¡ 1)
y
x
=
1
2
x+3) y=^12 x^2 +3xb When x=4, y=^12 (4)^2 + 3(4)
=20yO x 35(3 11),BvO x(2 4),(8 7),yO ~`x(4 2),(8 5),The graph of
y
x
againstxis linear.The gradient is
7 ¡ 4
8 ¡ 2
=
1
2
.The gradient is
5 ¡ 2
8 ¡ 4=
3
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Additional Mathematics
Y:\HAESE\CAM4037\CamAdd_07\188CamAdd_07.cdr Monday, 6 January 2014 9:18:59 AM BRIAN