9.8 Circles 797
Self Check 4
Find the area of the shaded
figure below. Round to the
nearest hundredth.
Now TryProblem 37
26 yd
10 yd
24 yd
8 in.
6 in.
10 in.
EXAMPLE (^4) Find the area of the shaded figure
on the right. Round to the nearest hundredth.
StrategyWe will find the area of the entire shaded
figure using the following approach:
WHYThe shaded figure is a combination of a triangular
region and two semicircular regions.
SolutionThe area of the triangle is
Since the formula for the area of a circle is , the formula for the area of a
semicircle is. Thus, the area enclosed by the smaller semicircle is
The area enclosed by the larger semicircle is
The total area is the sum of the three results:
Use a calculator to
perform the operations.
To the nearest hundredth, the area of the shaded figure is 88.40 in.^2.
Atotal 24 8 p12.5p88.4026494
Alarger semicircle
1
2
pr^2
1
2
p( 5 )^2
1
2
p(25)12.5p
Asmaller semicircle
1
2
pr^2
1
2
p( 4 )^2
1
2
p(16) 8 p
A^12 pr^2
Apr^2
Atriangle
1
2
bh
1
2
( 6 )( 8 )
1
2
(48) 24
AtotalAtriangleAsmaller semicircleAlarger semicircle
- 24 p m75.4 m 2.39.42 m 3. 36 p ft^2 113.1 ft^2 4.424.73 yd^2
ANSWERS TO SELF CHECKS
Using Your CALCULATOR Painting a Helicopter Landing Pad
Orange paint is available in gallon containers
at $19 each, and each gallon will cover
375 ft^2. To calculate how much the paint
will cost to cover a circular helicopter
landing pad 60 feet in diameter, we first
calculate the area of the helicopter pad.
This is the formula for the area of a circle.
Substitute one-half of 60 for r, the radius of the circular pad.
Write the product so that Pis the last factor.
The area of the pad is exactly ft^2. Since each gallon of paint will cover 375 ft^2 ,
we can find the number of gallons of paint needed by dividing by 375.
We can use a scientific calculator to make this calculation.
30 375
Because paint comes only in full gallons, the painter will need to purchase
8 gallons. The cost of the paint will be 8($19), or $152.
x^2 p 7.539822369
Number of gallons needed
302 p
375
302 p
302 p
302 p
Ap( 30 )^2
Apr^2
12.5
2 25.0
2
05
4
10
10
0