it be given that, on average, a telephone user is on the phone 5 minutes per
hour; an estimate of p is
The solution to this problem is given by
Ex ample 6. 3. Problem: let X 1 and X 2 be two independent random variables,
both having binomial distributions with parameters (n 1 ,p)and (n 2 , p), respect-
ively, and let Determine the distribution of random variable Y.
Answer: the characteristic functions of X 1 and X 2 are, according to the first
of Equations (6.8),
In view of Equation (4.71), the characteristic function of Y is simply the
product of and Thus,
By inspection, it is the characteristic function corresponding to a binomial
distribution with parameters H ence, we have
Generalizing the answer to Example 6.3, we have the following important
result as stated in Theorem 6.1.
Theorem 6.1:The binomial distribution generates itself under addition of
independent random variables with the same p.
Ex ample 6. 4. Problem: if random variables X and Y are independent binomial
distributed random variables with parameters (n 1 ,p)and (n 2 ,p), determine the
conditional probability mass function of X given that
166 Fundamentals of Probability and Statistics for Engineers
p
5
60
1
12
:
pX
2 pX
3
3
2
1
12
2
11
12
3
3
1
12
3
11
864
0 : 0197 :
YX 1 X 2.
X 1
t
pejtqn^1 ;X 2
t
pejtqn^2 :
X 1 (t) X 2 (t).
Y
tX 1
tX 2
t
pejtqn^1 n^2 :
(n 1 n 2 ,p).
pY
k
n 1 n 2
k
pkqn^1 n^2 k; k 0 ; 1 ;...;n 1 n 2 :
XYm; 0 mn 1 n 2 :