The corresponding probability distribution function iswhere m is the largest integer less than or equal to x. The mean and variance of
X can be found as follows:
In the above, the interchange of summation and differentiation is allowed
because 1. Following the same procedure, the variance has the form
Example 6.5.Problem: a driver is eagerly eyeing a precious parking space
some distance down the street. There are five cars in front of the driver, each of
which having a probability 0.2 of taking the space. What is the probability that
the car immediately ahead will enter the parking space?
Answer: for this problem, we have a geometric distribution and need to
evaluate for and Thus,
...pX(k)pqp
q^2 pk
1234567Figure6. 1 Geometricdistribution168 FundamentalsofProbabilityandStatisticsforEngineers
FX
xXmxk 1pX
kpqpqm^1 p
1 q
1 qq^2 qm^1 1 qm;
6 : 15 EfXgX^1
k 1kqk^1 ppX^1
k 1d
dqqkp
d
dqX^1
k 1qkp
d
dqq
1 q
1
p: 6 : 16
jqj<^2 X
1 p
p^2: 6 : 17
pX(k) k 5 p 0 :2.pX
5
0 : 8 ^4
0 : 2 0 : 82 ;pX(k)