the PDF associated with a Poisson–distributed random variable. The answer
to Example 6.11, for example, can easily be read off from Figure 6.4. We
mention again that a large number of computer software packages are
available to produce these probabilities. F or example, function POISSON in
Microsoft ExcelTM2000 gives the Poissonprobabilities given by Equation
(6.44) (see Appendix B).
Ex ample 6. 12. Problem: let X 1 and X 2 be two independent random variables,
both having Poisson distributions with parameters 1 and 2 , respectively, and
let Determine the distribution of Y.
Answer: we proceed by de te rmining first the characteristic functions of X 1
and X 2. They are
and
Owing to independence, the characteristic function of is simply the
product of and [see Equation (4.71)]. H ence,
By inspection, it is the characteristic function corresponding to a Poisson
distribution with parameter Its pmf is thus
As in the case of the binomial distribution, this result leads to the following
important theorem, Theorem 6.2.
Theorem 6.2:the Poisson distribution generates itself under addition of
independent random variables.
Ex ample 6. 13. Problem: suppose that the probability of an in sect laying r
eggs is 0,1,..., and that the probability of an egg de veloping is p.
Assuming mutual independence of individual developing processes, show that
the probability of a total of k survivors is
180 Fundamentals of Probability and Statistics for Engineers
1
YX 1 X 2.
X 1
tEfejtX^1 ge^1
X^1
k 0
ejtk 1 k
k!
exp 1
ejt 1
X 2
texp 2
ejt 1 :
Y,Y(t),
X 1 (t) X 2 (t)
Y
tX 1
tX 2
texp
1 2
ejt 1 :
1 2.
pY
k
1 2 kexp
1 2
k!
; k 0 ; 1 ; 2 ;...:
6 : 48
re/r!,r
(p)kep/k!.