The probability we are seeking is thus the volumeunder this surface over an
appropriate region R. For this problem, the region R is given by
and is shown in Figure 3.16 in the (x,y) plane.
The volume of interest can be found by inspection in this simple case.
Dividing R into three regions as shown, we have
P(they will meet) P X Y 10abxfX(x)1
b–aFigure 3. 14 A uniform density function, fX (x)fXY(x,y) y060603600x1Figure 3. 15 The joint probability density function fX Y (x,y), for Example 3.758 Fundamentals of Probability and Statistics for Engineers
R:jXYj 10
j j 2
5
10 10
2
p
50
2
p
= 3600