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Analog and Digital Filters 597


and the resulting network structure is illustrated in Figure 6.21.
Let us equate Equation 6.1 with Equation 6.2 resulting in the following:

Hs
ss
ss

ss
ss

ss
ss

()


























1


69


46


1


46


46


23


46


2
2

2
2

2
2

Hs
ss
ss

ss
ss

()

















1


69


46


1


1


23


46


2
2

2
+ 2

Let

Z


ss
ss










23


46


2
2 , note that^

()


()


1
2

Z


Zs
Zs




FIGURE 6.20
Structure for H(s) of R.14.144.

Z 1 (s)

Vi(s) Z 2 (s) Vo(s)

FIGURE 6.21
Reduction of H(s) of Figure 6.20.

Z 1 (s)
Z 2 (s)

Vi(s) 1 Ω Vo(s)
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