PRACTICAL MATLAB® FOR ENGINEERS PRACTICAL MATLAB

610 Practical MATLAB® Applications for Engineers

FIGURE 6.37
Circuit diagram of Example 6.3.

Vi(s) C = 1F Vo(s)

L = 1H

R = 1 Ω

The solutions of Example 6.3 are given by the script fi le shifting_LPF as follows:

ANALYTICAL Solution

Hs

R

sC

R

sC

sL

R

sC

R

sC

()







1

1

1

1

Hs

Vs

Vs

R

sC

R

sC

sL R

sC

o

i

()

()

()

 ^1







Hs

Vs

Vs

R

sC

sRL R

sC

L

C

o

i

()

()

()



Hs

Vs

Vs

R

sC sRL R

sC

L

C

o

i

()

()

()

 







Hs

Vs

Vs

R

s RLC Ls R

o

i

()

()

()



2 for 1RCL

Hs

Vs

Vs s s

o

i

()

()

()



1

(^21)
MATLAB Solution
% Script file: shifting _ LPF
% part(b), LPF with wn =1,R=L=C=1
num1=1;
den1= [1 1 1];
w = [0:.2:4];
H1 = freqs(num1,den1,w);