266 Coordinate geometry (Chapter 12)
3 Find the gradient of the line segment joining the following pairs of points:
a (2,3) and (7,4) b (5,7) and (1,6) c (1,¡2)and (3,6)
d (5,5) and(¡ 1 ,5) e (3,¡1) and(3,¡4) f (5,¡1)and (¡ 2 ,¡3)
g (¡ 5 ,2) and (2,0) h (0,¡1) and(¡ 2 ,¡3)
4 On the same set of axes draw lines through(1,2)with gradients of^34 ,^12 , 1 , 2 and 3.
5 On the same set of axes draw lines through(¡ 2 ,¡1)with gradients of 0 ,¡^12 ,¡ 1 and¡ 3.
USING GRADIENTS
In real life gradients occur in many situations, and can be interpreted in a variety of
ways.
For example, the sign alongside would indicate to motor vehicle drivers that there is an
uphill climb ahead.
Consider the situation in the graph alongside where a motor vehicle
travels at a constant speed for a distance of 600 km in 8 hours.
Clearly, the gradient of the line =
vertical step
horizontal step
=
600
8
=75
However, speed=
distance
time
=
600 km
8 hours
=75km/h.
So, in a graph of distance against time, thegradientcan be interpreted as thespeed.
In the following exercise we will consider a number of problems where gradient can be interpreted as a rate.
EXERCISE 12D.2
1 The graph alongside indicates the distances and corresponding
times as Tan walks a distance of 50 metres.
a Find the gradient of the line.
b Interpret the gradient found ina.
c Is the speed of the walker constant or variable? What evi-
dence do you have for your answer?
2 The graph alongside indicates the distances travelled by a
train. Determine:
a the average speed for the whole trip
b the average speed from
i AtoB ii BtoC
c the time interval over which the speed was greatest.
600
400
200
2468
time (hours)
distance (km)
O
20 40
50
25
distance (m)
time (s)
O
distance (km)
time (hours)
A
B
C
D
(1,¡65) (2,¡180)
(5,¡560)
(6,¡630)
O
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y:\HAESE\IGCSE01\IG01_12\266IGCSE01_12.CDR Friday, 3 October 2008 12:11:39 PM PETER