Cambridge International Mathematics

(Tina Sui) #1
Continuous data (Chapter 17) 359

Sometimes it is useful to know the number of scores that lie above or below a particular value. In
such situations it is convenient to construct acumulative frequency distribution tableand acumulative
frequency graphto represent the data.

The cumulative frequency gives arunning totalof the scores up to a particular value.
It is the total frequency up to a particular value.

From a frequency table we can construct a cumulative frequency column and then graph this data on a
cumulative frequency curve. The cumulative frequencies are plotted on the vertical axis.
From the cumulative frequency graph we can find:
² the median Q 2
² the quartiles Q 1 and Q 3
² percentiles

¾
These divide the ordered data into quarters.

ThemedianQ 2 splits the data into two halves, so it is50%of the way through the data.
Thefirst quartileQ 1 is the score value25%of the way through the data.
Thethird quartileQ 3 is the score value75%of the way through the data.
Thenth percentile Pn is the score valuen%of the way through the data.
So, P 25 =Q 1 ,P 50 =Q 2 and P 75 =Q 3.

Example 4 Self Tutor


Weight (w kg) Frequency
656 w< 70 1
706 w< 75 2
756 w< 80 8
806 w< 85 16
856 w< 90 21
906 w< 95 19
956 w< 100 8
1006 w< 105 3
1056 w< 110 1
1106 w< 115 1

The data shown gives the weights of 80 male basketball players.
a Construct a cumulative frequency distribution table.
b Represent the data on a cumulative frequency graph.
c Use your graph to estimate the:
i median weight
ii number of men weighing less than 83 kg
iii number of men weighing more than 92 kg
iv 85 th percentile.

a Weight (w kg) frequency cumulative frequency
656 w< 70 1 1
706 w< 75 2 3
756 w< 80 8 11
806 w< 85 16 27
856 w< 90 21 48
906 w< 95 19 67
956 w< 100 8 75
1006 w< 105 3 78
1056 w< 110 1 79
1106 w< 115 1 80

this is 1+2
this is 1+2+8

C CUMULATIVE FREQUENCY [11.7]


this 48 means that there are 48
players who weigh less than 90 kg,
so ( 90 , 48 ) is a point on the
cumulative frequency graph.

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Y:\HAESE\IGCSE01\IG01_17\359IGCSE01_17.CDR Tuesday, 18 November 2008 11:50:37 AM PETER

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