Cambridge International Mathematics

(Tina Sui) #1
718 ANSWERS

gx=¡ 6 h x=^252 i x= 150
2a(2,¡2) b (¡ 1 ,¡4) c (0,4)
d(0,1) e (¡ 2 ,¡15) f (¡ 2 ,¡5)
g(¡^32 ,¡^112 ) h (^52 ,¡^192 ) i (1,¡^92 )
3a ix-intercepts 4 ,¡ 2 , y-intercept¡ 8
iiaxis of symmetry x=1
iii vertex(1,¡9)
iv y=x^2 ¡ 2 x¡ 8

bix-intercepts 0 ,¡ 3 , y-intercept 0
iiaxis of symmetry x=¡^32
iii vertex(¡^32 ,¡^94 )
iv y=x^2 +3x

cix-intercepts 0 , 4 , y-intercept 0
iiaxis of symmetry x=2
iii vertex(2,4)
iv y=4x¡x^2

dix-intercept¡ 2 , y-intercept 4
iiaxis of symmetry x=¡ 2
iii vertex(¡ 2 ,0)
iv y=x^2 +4x+4

eix-intercepts¡ 4 , 1 , y-intercept¡ 4
iiaxis of symmetry x=¡^32
iii vertex(¡^32 ,¡^254 )
iv y=x^2 +3x¡ 4

fix-intercept 1 , y-intercept¡ 1
iiaxis of symmetry x=1
iii vertex(1,0)
iv y=¡x^2 +2x¡ 1

gix-intercepts¡ 2 ,¡ 4 , y-intercept¡ 8
iiaxis of symmetry x=¡ 3
iii vertex(¡ 3 ,1)
iv y=¡x^2 ¡ 6 x¡ 8

hix-intercepts 1 , 2 , y-intercept¡ 2
iiaxis of symmetry x=^32
iii vertex(^32 ,^14 )
iv y=¡x^2 +3x¡ 2

iix-intercepts^12 ,¡ 3 , y-intercept¡ 3
iiaxis of symmetry x=¡^54
iii vertex(¡^54 ,¡^498 )
iv y=2x^2 +5x¡ 3

jix-intercepts¡^32 , 4 , y-intercept¡ 12
iiaxis of symmetry x=^54
iii vertex(^54 ,¡^1218 )
iv y=2x^2 ¡ 5 x¡ 12

kix-intercepts^23 ,¡ 2 , y-intercept 4
iiaxis of symmetry x=¡^23
iii vertex(¡^23 ,^163 )
iv y=¡ 3 x^2 ¡ 4 x+4

lix-intercepts 0 , 20 , y-intercept 0
iiaxis of symmetry x=10
iii vertex(10,25)
iv y=¡^14 x^2 +5x

4ax=2 bx=1 c x=¡ 4

y

x

-12

!\=\Tr_


  • Ew_


(_\' -Tr Q_Wi_Q_)

4

O

y

x

4
We_

!\=\-We_

(-We_\'Qd_Y_)

-2
O

y

x

(10' 25)

20

!\=\10

O

O

y

-3 x

!\=\-Ew_

(-Ew_\' -Or_)

O

y

x

(2' 4)

4

!\=\2

O

y

(-2' 0) x

4

!\=\-2

O

y
x
1
-4
(-\Ew_\' -\Wf_T_)

!\=\-Ew_

-4

O

y
x

-1

(1' 0)

!\=\1

y
-2 x

-8

4

(1' -9)

!\=\1

O

y
x
-4 -2

-8

(-3' 1)

!\=\-3

O

y

x
-2

1 2

!\=\Ew_

(Ew_\'Qr_)
O

y

-3 -3 x

!\=\-\Tr_

(-\Tr_\' -\Rk_O_)

Qw_
O

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Y:\HAESE\IGCSE01\IG01_an\718IB_IGC1_an.CDR Wednesday, 19 November 2008 3:59:43 PM PETER

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