The Chemistry Maths Book, Second Edition

(Grace) #1

28 Chapter 1Numbers, variables, and units


In this form the equation is often referred to as the ‘Schrödinger equation in atomic


units’. The results of computations are then numbers that must be reinterpreted


as physical quantities. For example, the quantity Ein equation (1.18) is an energy.


Solution of equation (1.19) gives the numbersE 1 = 1 − 122 n


2

, for all positive integers n,


and these numbers are then interpreted as the energiesE 1 = 1 − 122 n


2

E


h

.


EXAMPLE 1.21The atomic unit of energy


By Coulomb’s law, the potential energy of interaction of chargesq


1

andq


2

separated


by distance ris


whereε


0

1 = 1 8.85419 1 × 110


− 12

F m


− 1

is the permittivity of a vacuum. For chargesq


1

1 = 1 Z


1

e


andq


2

1 = 1 Z


2

eseparated by distancer 1 = 1 Ra


0

,


(i) To show that the unit is the hartree unitE


h

in Table 1.4, usea


0

1 = 14 πε


0

A


2

2 m


e

e


2

:


(ii) To calculate the value of E


h

in SI units, use the values of eand a


0

given in


Table 1.4. Then


= 1 (4.35975 1 × 110


− 3

) 1 × 1 (10


− 15

) 1 × 1 (C


2

1 F


− 1

)


From the definitions of the coulomb C and farad F in Table 1.2,F 1 = 1 C


2

1 J


− 1

so that


C


2

1 F


− 1

1 = 1 J. Therefore


0 Exercise 108


e


a


E


2

00

18

4


10


πε


=×=



4.35975 J


h

e


a


2

00

2

4


1 60218


πε 4 3 14159 8 85419 5 29177


=


×××



.


...











×


×


×










×


−−

−−

10 10


10 10


19 19

12 11

2

C


F m m











1

e


a


e


me


2

00

2

0

0

2

2

44


4


ππ


π


εε


ε


=










÷










=





e

ee


me me


2

0

2

0

2

4

2

4


416


π


ππ


ε


ε










×










=


ee

 εε


0

22




=E


h

V


ZZ


R


e


a


=


















12

2

00

4 πε


V


qq


r


=


12

0

4 πε

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