The Chemistry Maths Book, Second Edition

(Grace) #1

17.4 The solution of linear equations 485


The sum of (2) and (3) is now equal to twice (1), but this means that equation (1)


contains no information not already contained in the other two equations. The


equations are said to be linearly dependent, and each equation can be expressed as a


linear combination of the others. We have effectively only two equations in three


unknowns. For example, solving (1) and (2), or any pair, for xand yin terms of zgives


(17.33)


and this is a solution of the system (17.32) for every value of z.


0 Exercise 17


Homogeneous equations


When at least one of the quantitiesb


k

on the right sides of equations (17.26) is not


zero, the equations are called inhomogeneous equations. When all theb


k

are zero,


they are calledhomogeneous equations:


a


11

x


1

1 + 1 a


12

x


2

1 + 1 a


13

x


3

1 + 1  1 + 1 a


1 n

x


n

1 = 10


a


21

x


1

1 + 1 a


22

x


2

1 + 1 a


23

x


3

1 + 1  1 + 1 a


2 n

x


n

1 = 10


a


31

x


1

1 + 1 a


32

x


2

1 + 1 a


33

x


3

1 + 1  1 +a


3 n

x


n

1 = 10 (17.34)


  


a


n 1

x


1

1 + 1 a


n 2

x


2

1 + 1 a


n 3

x


3

1 + 1  1 + 1 a


nn

x


n

1 = 10


Only the zero solution (17.30) exists ifD 1 ≠ 10 , but other solutions also exist when


D 1 = 10. For example, the system


(1) 2x 1 + 12 y 1 + z 1 = 10


(2) x+ 12 y 1 − 12 z 1 = 10 (17.35)


(3) 3x 1 + 12 y 1 + 14 z 1 = 10


hasD 1 = 10 and, like (17.32), the equations are linearly dependent. One solution is the


trivial (zero) solutionx 1 = 1 y 1 = 1 z 1 = 10. Nonzerosolutions are obtained by solving any


pair of the equations for xand yin terms of z:


(17.36)


for all values of z. A uniquesolution is obtained only if a further, independent, relation


amongst x, y, and zis known.


This example demonstrates one of the most important theorems of systems of


linear equations:


A system of homogeneous linear equations has nontrivial


solution only if the determinant of the coefficients is zero.


xz y


z


=− , 3 =


5


2


xzyz=−,13 3 = −


1


2


() 516

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