2.5 Polynomials 45
EXAMPLE 2.17Case
The quadratic
2 x
2
1 − 18 x 1 + 181 = 1 2(x 1 − 1 2)
2
has zero discriminant and the double root(two equal roots)x 1 = 1 2.
0 Exercises 47, 48
When the discriminant is negative, formula (2.20) requires the taking of the square
root of a negative number, and the result is not a real number. In this case the roots of
the quadratic are a pair of complex numbers involving the square root of
(see Section 8.2)
EXAMPLE 2.18Case
The quadratic
x
2
1 − 14 x 1 + 113
has a pair of complex roots x
1
and x
2
given by
The roots arex
1
1 = 121 + 13 iandx
2
1 = 121 − 13 iand the factorized form of the quadratic is
(x 1 − 1 x
1
)(x 1 − 1 x
2
).
0 Exercises 49, 50
0 Exercises 51, 52
For very large (‘large enough’) values of |x|the term in x
2
in the quadratic
f(x) 1 = 1 ax
2
1 + 1 bx 1 + 1 cis very much larger in magnitude than the other two terms. Thus,
dividing the function byx
2
,
This means that for large enough positive and negative values of x, the function behaves
like the simpler function ax
2
, and can sometimes be replaced by it. In general for the
polynomial of degree n, equation (2.9),
fx
x
a
b
x
c
x
ax
()
22
=+ + → as →±∞
xi=
±−
=±
436
2
23
bac
2
−< 40.
−=−11:i
bac
2
−= 40.