Electrical Power Systems Technology

(Elle) #1

346 Electrical Power Systems Technology


Find: the total light output from the lighting system.
Solution:



  1. Find the total light output from the lamps.


3000 lumens per lamp × 16 luminaires ×
2 lamps per luminaire = 96,000 lumens


  1. Find the total light output:


light output = total lumens × CD × DF
= 96,000 × 0.45 × 0.90
= 38,880 lumens


The distribution of light output onto work surfaces must also be con-
sidered. The CD and the DF are used to find the total light output of a
lighting system. A greater light output is required for larger areas. The
light output to a work surface is expressed as lumens per square foot, or
footcandles. A light meter is used to measure the quantity of light that
reaches a surface.
The following two formulas are useful for finding the required lu-
mens for a work area, or the light output available from a particular light-
ing system:


desired footcandles × room area in ft.
total lumens = —————————————————
CD × DF


and


total lumens × CD × DF
footcandles available = —————————————
room area in feet


Sample Problem:
Given: a lighting system with 12,000 total lumen output, luminaire
CD = 0.83 and DF = 0.85, is installed in a 600 sq. ft. room.
Find: the footcandles of light available on the work surface.
Solution:


lumens × CD × DF
FC = ————————
room area

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