Draft

14.3ApproximateAnalysisof Buildings 247

+2.5

K +3.75

K

-3.75

K

+3.0

K

-3.0

K

+5.0

K

-5.0

K

+7.5

K

-7.5

K

-0.64

K

-0.80

K

+0.51

K

+0.93

K

+0.81

K

+0.45

K

-0.70

K

-0.56

K

-6.0

K

+6.0

K

-2.5

K

Figure14.17:ApproximateAnalysisof a Building;ShearsDueto VerticalLoads

HorizontalLoads,PortalMethod

1. ColumnShears

V 5 =

15

(2)(3)

= 2 : 5 k

V 6 = 2(V 5 ) = (2)(2:5) = 5 k

V 7 = 2(V 5 ) = (2)(2:5) = 5 k

V 8 = V 5 = 2 : 5 k

V 1 =

15+30

(2)(3)

= 7 : 5 k

V 2 = 2(V 1 ) = (2)(7:5) = 15 k

V 3 = 2(V 1 ) = (2)(2:5) = 15 k

V 4 = V 1 = 7 : 5 k

2. TopColumnMoments

M

top

5

=

V 1 H 5

2

=

(2:5)(14)

2

= 17 : 5 k.ft

M

bot

5

= M

top

5

= 17 : 5 k.ft

M

top

6

=

V 6 H 6

2

=

(5)(14)

2

= 35 : 0 k.ft

M

bot

6

= M

top

6

= 35 : 0 k.ft

M

top

7

=

V

up

7 H^7

2

=

(5)(14)

2

= 35 : 0 k.ft

M

bot

7

= M

top

7

= 35 : 0 k.ft

M

top

8

=

V

up

8

H 8

2

=

(2:5)(14)

2

= 17 : 5 k.ft

M

bot

8 = M

top

8

= 17 : 5 k.ft