7 Complements 211It was conjectured by Frobenius (1913) that a Markov triple is uniquely determined
by its greatest element. This has been verified whenever the greatest element does not
exceed 10^140. It has also been proved when the greatest element is a prime (and in
some other cases) by Baragar (1996), using the theory of quadratic fields.
7 Complements...............................................
There is an important analogue of the continued fraction algorithm for infinite series.
LetKbe an arbitrary field and letFdenote the set of all formal Laurent series
f=∑
n∈Zαntnwith coefficientsαn∈Ksuch thatαn=0 for at most finitely manyn>0. If
g=∑
n∈Zβntnis also an element ofF, and if we define addition and multiplication by
f+g=∑
n∈Z(αn+βn)tn, fg=∑
n∈Zγntn,whereγn=
∑
j+k=nαjβk,thenFacquires the structure of a commutative ring. In
fact,Fis a field. For, iff=
∑
n≤vαnt
n,whereαv=0, we obtaing=∑
n≤−vβnt
nsuch thatfg=1 by solving successively the equations
αvβ−v= 1
αvβ−v− 1 +αv− 1 β−v= 0
αvβ−v− 2 +αv− 1 β−v− 1 +αv− 2 β−v= 0
·····Define the absolute value of an elementf=∑
n∈Zαnt
nofFby putting|O|= 0 , |f|= 2 v(f) iff=O,wherev(f)is the greatest integernsuch thatαn=0. It is easily verified that
|fg|=|f||g|,|f+g|≤max(|f|,|g|),and|f+g|=max(|f|,|g|)if|f| =|g|.
For any f=
∑
n∈Zαntn∈F,letf=∑
n≥ 0αntn, {f}=∑
n< 0αntndenote respectively its polynomial and strictly proper parts. Then|{f}|< 1, and
|f| = |f|if|f|≥1, i.e. iff =O.