SOLVING EQUATIONS BY ITERATIVE METHODS 85
A
Thus, r 2 = 3 −
19. 35
− 463. 7
= 3 + 0. 042
= 3. 042 = 3 .04,
correct to 3 significant figure
Similarly, r 3 = 3. 042 −
f(3.042)
f′(3.042)
= 3. 042 −
(− 1 .146)
(− 513 .1)
= 3. 042 − 0. 0022 = 3. 0398 = 3 .04,
correct to 3 significant figure.
Sincer 2 andr 3 are the same when expressed to the
required degree of accuracy, then the required root
is3.04, correct to 3 significant figures.
Now try the following exercise.
Exercise 41 Further problems on Newton’s
method
In Problems 1 to 7, useNewton’s methodto
solve the equations given to the accuracy stated.
1.x^2 − 2 x− 13 =0, correct to 3 decimal
places. [−2.742, 4.742]
- 3x^3 − 10 x=14, correct to 4 significant
figures. [2.313]
3.x^4 − 3 x^3 + 7 x=12, correct to 3 decimal
places. [−1.721, 2.648]
- 3x^4 − 4 x^3 + 7 x− 12 =0, correct to 3 deci-
mal places. [−1.386, 1.491]
5. 3 lnx+ 4 x=5, correct to 3 decimal places.
[1.147]
6.x^3 =5 cos 2x, correct to 3 significant fig-
ures. [−1.693,−0.846, 0.744]
- 300e−^2 θ+
θ
2
=6, correct to 3 significant
figures. [2.05]
- Solve the equations in Problems 1 to 5,
Exercise 39, page 80 and Problems 1 to
4, Exercise 40, page 83 using Newton’s
method. - A Fourier analysis of the instantaneous
value of a waveform can be represented by:
y=
(
t+
π
4
)
+sint+
1
8
sin 3t
Use Newton’s method to determine the
value oftnear to 0.04, correct to 4 decimal
places, when the amplitude,y, is 0.880.
[0.0399]
- A damped oscillation of a system is given
by the equation:
y=− 7 .4e^0.^5 tsin 3t.
Determine the value oftnear to 4.2, correct
to 3 significant figures, when the magnitude
yof the oscillation is zero. [4.19]
- The critical speeds of oscillation,λ,ofa
loaded beam are given by the equation:
λ^3 − 3. 250 λ^2 +λ− 0. 063 = 0
Determine the value ofλwhich is approx-
imately equal to 3.0 by Newton’s method,
correct to 4 decimal places. [2.9143]