100 NUMBER AND ALGEBRA
Problem 7. Simplify
F·G·H+F·G·H+F·G·HWith reference to Table 11.8: ReferenceF·G·H+F·G·H+F·G·H
=F·G·(H+H)+F·G·H 5
=F·G· 1 +F·G·H 10
=F·G+F·G·H 12
=G·(F+F·H)5Problem 8. Simplify
F·G·H+F·G·H+F·G·H+F·G·HWith reference to Table 11.8: ReferenceF·G·H+F·G·H+F·G·H+F·G·H
=G·H·(F+F)+G·H·(F+F)5
=G·H· 1 +G·H· 110
=G·H+G·H 12
=H·(G+G)5
=H· 1 =H 10 and 12Problem 9. SimplifyA·C+A·(B+C)+A·B·(C+B)
using the rules of Boolean algebra.With reference to Table 11.8: ReferenceA·C+A·(B+C)+A·B·(C+B)
=A·C+A·B+A·C+A·B·C
+A·B·B 5
=A·C+A·B+A·C+A·B·C
+A· 014
=A·C+A·B+A·C+A·B·C 11
=A·(C+B·C)+A·B+A·C 5
=A·(C+B)+A·B+A·C 17
=A·C+A·B+A·B+A·C 5
=A·C+B·(A+A)+A·C 5
=A·C+B· 1 +A·C 10
=A·C+B+A·C 12Problem 10. Simplify the expressionP·Q·R+P·Q·(P+R)+Q·R·(Q+P),
using the rules of Boolean algebra.With reference to Table 11.8: ReferenceP·Q·R+P·Q·(P+R)+Q·R·(Q+P)
=P·Q·R+P·Q·P+P·Q·R
+Q·R·Q+Q·R·P 5
=P·Q·R+ 0 ·Q+P·Q·R+ 0 ·R
+P·Q·R 14
=P·Q·R+P·Q·R+P·Q·R 7 and 11
=P·Q·R+P·Q·R 9
=P·R·(Q+Q)5
=P·R· 110
=P·R 12Now try the following exercise.Exercise 47 Further problems on the laws
and the rules of Boolean algebraUse the laws and rules of Boolean algebra
given in Table 11.8 to simplify the following
expressions:1.P·Q+P·Q [P]2.P·Q+P·Q+P·Q [P+P·Q]3.F·G+F·G+G·(F+F)[G]4.F·G+F·(G+G)+F·G [F]- (P+P·Q)·(Q+Q·P)[P·Q]
6.F·G·H+F·G·H+F·G·H
[H·(F+FG]7.F·G·H+F·G·H+F·G·H
[F·G·H+G·H]8.P·Q·R+P·Q·R+P·Q·R
[Q·R+P·Q·R]9.F·G·H+F·G·H+F·G·H+F·G·H
[G]10.F·G·H+F·G·H+F·G·H+F·G·H
[F·H+G·H]11.R·(P·Q+P·Q)+R·(P·Q+P·Q)
[P·R+P·R]12.R·(P·Q+P·Q+P·Q)+P·(Q·R+Q·R)
[P+Q·R]