INTRODUCTION TO TRIGONOMETRY 129
B
Figure 12.27
Applying the sine rule:
PR
sin 120◦
=
PQ
sinR
from which,
sinR=
PQsin 120◦
PR
=
(4.0) sin 120◦
10. 0
= 0. 3464
Hence ∠R=sin−^10. 3464 = 20 ◦ 16 ′ (or 159◦ 44 ′,
which is impossible in this case).
∠P= 180 ◦− 120 ◦− 20 ◦ 16 ′= 39 ◦ 44 ′,which is the
inclination of the jib to the vertical.
Applying the sine rule:
10. 0
sin 120◦
=
QR
sin 39◦ 44 ′
from which,length of tie,
QR=
10 .0 sin 39◦ 44 ′
sin 120◦
=7.38 m
Now try the following exercise.
Exercise 59 Further problems on practical
situations involving trigonometry
- A shipPsails at a steady speed of 45 km/h in
a direction of W 32◦N (i.e. a bearing of 302◦)
from a port. At the same time another shipQ
leaves the port at a steady speed of 35 km/h
in a direction N 15◦E (i.e. a bearing of 015◦).
Determine their distance apart after 4 hours.
[193 km] - Two sides of a triangular plot of land are
52.0 m and 34.0 m, respectively. If the area of
the plot is 620 m^2 find (a) the length of fen-
cing required to enclose the plot and (b) the
angles of the triangular plot.
[(a) 122.6 m (b) 94◦ 49 ′,40◦ 39 ′,44◦ 32 ′]
- A jib crane is shown in Fig. 12.28. If the tie
rodPRis 8.0 long andPQis 4.5 m long deter-
mine (a) the length of jibRQand (b) the angle
between the jib and the tie rod.
[(a) 11.4 m (b) 17◦ 33 ′]
Figure 12.28
- A building site is in the form of a quadri-
lateral as shown in Fig. 12.29, and its area
is 1510 m^2. Determine the length of the
perimeter of the site. [163.4 m]
Figure 12.29
- Determine the length of membersBFandEB
in the roof truss shown in Fig. 12.30.
[BF= 3 .9m,EB= 4 .0m]