382 INTEGRAL CALCULUS
When areaPQRSis rotated about axisXXthe vol-
ume generated is that of the pulley. The centroid of
the semicircular area removed is at a distance of
4 r
3 π
from its diameter (see ‘Engineering Mathematics4th
edition’, page 471), i.e.
4(1.0)
3 π
, i.e. 0.424 cm from
PQ. Thus the distance of the centroid fromXXis
5. 0 − 0 .424, i.e. 4.576 cm.
The distance moved through in one revolution by the
centroid is 2π(4.576) cm.
Area of semicircle=
πr^2
2
=
π(1.0)^2
2
=
π
2
cm^2
By the theorem of Pappus,
volume generated=area×distance moved by
centroid=
(π
2
)
(2π)(4.576).
i.e.volume of metal removed=45.16 cm^3
Mass of metal removed=density×volume
=8000 kg m−^3 ×
45. 16
106
m^3
= 0 .3613 kg or 361.3g
volume of pulley=volume of cylindrical disc
−volume of metal removed
=π(5.0)^2 (2.0)− 45. 16
=111.9 cm^3
Mass of pulley=density×volume
=8000 kg m−^3 ×
111. 9
106
m^3
=0.8952 kgor895.2 g
Now try the following exercise.
Exercise 152 Further problems on the the-
orem of Pappus
- A right angled isosceles triangle having a
hypotenuse of 8 cm is revolved one revolution
about one of its equal sides as axis. Deter-
mine the volume of the solid generated using
Pappus’ theorem. [189.6 cm^3 ] - Using (a) the theorem of Pappus, and (b) inte-
gration, determine the position of the centroid
of a metal template in the form of a quadrant
of a circle of radius 4 cm. (The equation of a
circle, centre 0, radiusrisx^2 +y^2 =r^2 ).
⎡
⎢
⎣
On the centre line, distance
2 .40 cm from the centre,
i.e. at co-ordinates
(1.70, 1.70)
⎤
⎥
⎦
- (a) Determine the area bounded by the curve
y= 5 x^2 , the x-axis and the ordinates
x=0 andx=3.
(b) If this area is revolved 360◦about (i) the
x-axis, and (ii) they-axis, find the vol-
umes of the solids of revolution produced
in each case.
(c) Determine the co-ordinates of the cen-
troid of the area using (i) integral calcu-
lus, and (ii) the theorem of Pappus.
⎡
⎢
⎣
(a) 45 square units
(b) (i) 1215πcubic units
(ii) 202.5πcubic units
(c) (2.25, 13.5)
⎤
⎥
⎦
- A metal disc has a radius of 7.0 cm and is
of thickness 2.5 cm. A semicircular groove of
diameter 2.0 cm is machined centrally around
the rim to form a pulley. Determine the vol-
ume of metal removed using Pappus’ theorem
and express this as a percentage of the origi-
nal volume of the disc. Find also the mass of
metal removed if the density of the metal is
7800 kg m−^3.
[64.90 cm^3 , 16.86%, 506.2 g]
For more on areas, mean and r.m.s. values, volumes
and centroids, see ‘Engineering Mathematics4th
edition’, Chapters 54 to 57.
38.7 Second moments of area of
regular sections
Thefirst moment of areaabout a fixed axis of a
lamina of areaA, perpendicular distanceyfrom the
centroid of the lamina is defined asAycubic units.
Thesecond moment of areaof the same lamina as
above is given byAy^2 , i.e. the perpendicular distance