524 DIFFERENTIAL EQUATIONS
from which,X=Acospx+Bsinpx
and Y=Cepy+De−py
or Y=Ccoshpy+Dsinhpy
or Y=Esinhp(y+φ)
Hence u(x,y)=XY
={Acospx+Bsinpx}{Esinhp(y+φ)}
or u(x,y)
={Pcospx+Qsinpx}{sinhp(y+φ)}
whereP=AEandQ=BE.
The first boundary condition is:u(0,y)=0, hence
0 =Psinhp(y+φ) from which,P=0.
Hence,u(x,y)=Qsinpxsinhp(y+φ).
The second boundary condition is:u(1,y)=0, hence
0 =Qsinp(1) sinhp(y+φ) from which,
sinp=0, hence,p=nπ forn=1, 2, 3,...
The third boundary condition is:u(x,0)=0, hence,
0 =Qsinpxsinhp(φ) from which,
sinhp(φ)=0 andφ=0.
Hence,u(x,y)=Qsinpxsinhpy.
Since there are many solutions for integer values ofn,
u(x,y)=
∑∞
n= 1
Qnsinpxsinhpy
=
∑∞
n= 1
Qnsinnπxsinhnπy (a)
The fourth boundary condition is:u(x,1)= 4 =f(x),
hence,f(x)=
∑∞
n= 1
Qnsinnπxsinhnπ(1).
From Fourier series coefficients,
Qnsinhnπ= 2 ×the mean value of
f(x) sinnπxfromx=0tox= 1
i.e. =
2
1
∫ 1
0
4 sinnπxdx
= 8
[
−
cosnπx
nπ
] 1
0
=−
8
nπ
(cosnπ−cos 0)
=
8
nπ
( 1 −cosnπ)
=0 (for even values ofn),
=
16
nπ
(for odd values ofn)
Hence, Qn=
16
nπ(sinhnπ)
=
16
nπ
cosechnπ
Hence, from equation (a),
u(x,y)=
∑∞
n= 1
Qnsinnπxsinhnπy
=
16
π
∑∞
n(odd)= 1
1
n
(cosechnπsinnπxsinhnπy)
Now try the following exercise.
Exercise 204 Further problems on the
Laplace equation
- A rectangular plate is bounded by the
linesx=0,y=0,x=1 andy= 3 .Apply the
Laplace equation
∂^2 u
∂x^2
+
∂^2 u
∂y^2
=0 to deter-
mine the potential distributionu(x,y) over
the plate, subject to the following boundary
conditions:
u=0 whenx= 00 ≤y≤2,
u=0 whenx= 10 ≤y≤2,
u=0 wheny= 20 ≤x≤1,
u=5 wheny= 30 ≤x≤ 1
⎡
⎣u(x,y)=^20
π
∑∞
n(odd)= 1
1
n
cosechnπsinnπxsinhnπ(y−2)
⎤
⎦
- A rectangular plate is bounded by the
linesx=0,y=0,x=3,y= 2 .Determine the
potential distribution u(x,y) over the rec-
tangle using the Laplace equation
∂^2 u
∂x^2
+
∂^2 u
∂y^2
=0, subject to the following
boundary conditions:
u(0,y)= 00 ≤y≤2,
u(3,y)= 00 ≤y≤2,
u(x,2)= 00 ≤x≤3,
u(x,0)=x(3−x)0≤x≤ 3
⎡
⎣u(x,y)=^216
π^3
∑∞
n(odd)= 1
1
n^3 cosech
2 nπ
3 sin
nπx
3 sinh
nπ
3 (2−y)
⎤
⎦