40 NUMBER AND ALGEBRA
When the voltage is 30.0 volts, 30. 0 =2090 e
−t
(^0) ,
hence e
−t
(^0) =
0
2090
and e
t
(^0) =
2090
0
= 69. 67
Taking Napierian logarithms gives:
t
0
=ln 69. 67 = 4. 2438
from which, timet=(12.0)(4.2438)=50.9 ms
Now try the following exercise.
Exercise 23 Further problems on reducing
exponential laws to linear form
Atmospheric pressurepis measured at vary-
ing altitudeshand the results are as shown
below:
Altitude,hm pressure,pcm
500 73.39
1500 68.42
3000 61.60
5000 53.56
8000 43.41
Show that the quantities are related by the
lawp=aekh, whereaandkare constants.
Determine the values ofaandkand state
the law. Find also the atmospheric pressure
at 10 000 m.
[
a=76,k=− 7 × 10 −^5 ,
p=76 e−^7 ×^10
− (^5) h
,37.74 cm
]
- At particular times,tminutes, measurements
are made of the temperature,θ◦C, of a cooling
liquid and the following results are obtained:
Temperatureθ◦C Timetminutes
92.2 10
55.9 20
33.9 30
20.6 40
12.5 50
Prove that the quantities follow a law of the
formθ=θ 0 ekt, whereθ 0 andkare constants,
and determine the approximate value ofθ 0
andk.
[θ 0 =152,k=− 0 .05]