THE BINOMIAL SERIES 65
A
New values of b and l are (1+ 0 .035)b and
(1− 0 .025)lrespectively.
New second moment of area
=
1
12
[(1+ 0 .035)b][(1− 0 .025)l]^3
=
bl^3
12
(1+ 0 .035)(1− 0 .025)^3
≈
bl^3
12
(1+ 0 .035)(1− 0 .075), neglecting
powers of small terms
≈
bl^3
12
(1+ 0. 035 − 0 .075), neglecting
products of small terms
≈
bl^3
12
(1− 0 .040) or (0.96)
bl^3
12
, i.e. 96%
of the original second moment of area
Hence the second moment of area is reduced by
approximately 4%.
Problem 18. The resonant frequency of a
vibrating shaft is given by:f=
1
2 π
√
k
I
, where
kis the stiffness andI is the inertia of the
shaft. Use the binomial theorem to determine
the approximate percentage error in determin-
ing the frequency using the measured values of
kandI when the measured value ofkis 4%
too large and the measured value ofIis 2% too
small.
Letf,kandIbe the true values of frequency, stiffness
and inertia respectively. Since the measured value of
stiffness,k 1 , is 4% too large, then
k 1 =
104
100
k=(1+ 0 .04)k
The measured value of inertia,I 1 , is 2% too small,
hence
I 1 =
98
100
I=(1− 0 .02)I
The measured value of frequency,
f 1 =
1
2 π
√
k 1
I 1
=
1
2 π
k
1
2
1 I
−^12
1
=
1
2 π
[(1+ 0 .04)k]
1
(^2) [(1− 0 .02)I]−
1
2
1
2 π
(1+ 0 .04)
1
(^2) k
1
(^2) (1− 0 .02)−
1
(^2) I−
1
2
1
2 π
k
1
(^2) I−
1
(^2) (1+ 0 .04)
1
(^2) (1− 0 .02)−
1
2
i.e. f 1 =f(1+ 0 .04)
1
(^2) (1− 0 .02)−
1
2
≈f
[
1 +
(
1
2
)
(0.04)
][
1 +
(
−
1
2
)
(− 0. 02 )
]
≈f(1+ 0 .02)(1+ 0 .01)
Neglecting the products of small terms,
f 1 ≈(1+ 0. 02 + 0 .01)f≈ 1. 03 f
Thus the percentage error in f based on the
measured values of k and I is approximately
[(1.03)(100)−100], i.e.3% too large.
Now try the following exercise.
Exercise 35 Further practical problems
involving the binomial theorem
- Pressurepand volumev are related by
pv^3 =c, wherecis a constant. Determine the
approximate percentage change incwhenp
is increased by 3% andvdecreased by 1.2%.
[0.6% decrease] - Kinetic energy is given by^12 mv^2. Deter-
mine the approximate change in the kinetic
energy when massmis increased by 2.5%
and the velocityvis reduced by 3%.
[3.5% decrease] - An error of+1.5% was made when meas-
uring the radius of a sphere. Ignoring the
products of small quantities determine the
approximate error in calculating (a) the vol-
ume, and (b) the surface area.
[
(a) 4.5% increase
(b) 3.0% increase
]
- The power developed by an engine is given
byI=kPLAN, wherekis a constant. Deter-
mine the approximate percentage change in
the power whenPandAare each increased
by 2.5% andLandNare each decreased by
1.4%. [2.2% increase]