188 C H A P T E R 3: The Laplace Transform
0 5 10
00.51tu(t)0 5 10− 101tcos(5t)u(t)0 5 10
00.51texp(−0.5t)u(t)0 5 10− 101tcos(5t)exp(−0.5t)u(t)− 2 − 1 0 1− 10010σjΩFIGURE 3.10
For poles shown in the middle, possible signals are displayed around them anti–clockwise from bottom right.
The poles= 0 corresponds to a unit-step signal; the complex conjugate poles on thejaxis correspond to a
sinusoid; the pair of complex conjugate poles with a negative real part provides a sinusoid multiplied by an
exponential; and the pole in the negative real axis gives a decaying exponential. The actual amplitudes and
phases are determined by the other poles and by the zeros.3.3.2 Differentiation
For a signalf(t)with Laplace transformF(s)its one-sided Laplace transform of its first-and second-order
derivatives areL[
df(t)
dt
u(t)]
=sF(s)−f( 0 −) (3.11)