3.4 Inverse Laplace Transform 213convergenceRe(s) <2. That this is so is confirmed by the intersection of these two regions of
convergence that gives[Re(s) >− 2 ]∩[Re(s) < 2 ]=− 2 <Re(s) < 2As such, we havex(t)=−0.25e−^2 tu(t)−0.25e^2 tu(−t) nnExample 3.21
Consider the transfer functionH(s)=s
(s+ 2 )(s− 1 )=
2 / 3
s+ 2+
1 / 3
s− 1
with a zero ats=0, and poles ats=−2 ands=1. Find out how many impulse responses can be
connected withH(s)by considering different possible regions of convergence and by determining
in which cases the system withH(s)as its transfer function is BIBO stable.SolutionThe following are the different possible impulse responses:n If ROC:Re(s) >1, the impulse responseh 1 (t)=( 2 / 3 )e−^2 tu(t)+( 1 / 3 )etu(t)corresponding toH(s)with this region of convergence is causal. The corresponding system is
unstable—due to the pole in the right-hands-plane, which will make the impulse response
grow astincreases.
n If ROC:− 2 <Re(s) <1, the impulse response corresponding toH(s)with this region of
convergence is noncausal, but the system is stable. The impulse response would beh 2 (t)=( 2 / 3 )e−^2 tu(t)−( 1 / 3 )etu(−t)Notice that the region of convergence includes thejaxis, and this guarantees the stability
(verify thath 2 (t)is absolutely integrable), and as we will see later, also the existence of the
Fourier transform ofh 2 (t).
n If ROC:Re(s) <−2, the impulse response in this case would be anti-causal, and the system is
unstable (please verify it), as the impulse response ish 3 (t)=−( 2 / 3 )e−^2 tu(−t)−( 1 / 3 )etu(−t) nTwo very important generalizations of the results in this example are:
n An LTI with a transfer functionH(s)and region of convergenceRis BIBO stable if thejaxis is contained
in the region of convergence.