Signals and Systems - Electrical Engineering

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242 C H A P T E R 4: Frequency Analysis: The Fourier Series


FIGURE 4.1
RC circuit and corresponding phasor
circuit.

vs(t)

1 Ω

1F vc(t)

+

− +


1

−j

+


Vc

+


Vs

corresponding tovc(t):

Vc
Vs

=

−j
1 −j

=

−j( 1 +j)
2

=


2

2

∠−π/ 4

SinceVs= 4 ∠π/4, then

Vc= 2


2 ∠ 0

so that in the steady state,

vc(t)= 2


2 cos(t)

n Eigenfunction approach.Considering the output is the voltage across the capacitor and the input
is the voltage source, the transfer function is obtained using voltage division as

H(s)=

Vc(s)
Vs(s)

=

1 /s
1 + 1 /s

=

1

s+ 1

so that the system frequency response at the input frequency 0 =1 is

H(j 1 )=


2

2

∠−π/ 4

According to the eigenfunction property the steady-state response of the capacitor is

vc(t)= 4 |H(j 1 )|cos(t+π/ 4 +∠H(j 1 ))

= 2


2 cos(t)

which coincides with the solution found using phasors. n

nExample 4.2
An ideal communication system provides as output the input signal with only a possible delay in
the transmission. Such an ideal system does not cause any distortion to the input signal beyond
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