242 C H A P T E R 4: Frequency Analysis: The Fourier Series
FIGURE 4.1
RC circuit and corresponding phasor
circuit.vs(t)1 Ω1F vc(t)+− +−1−j+−Vc+−Vscorresponding tovc(t):Vc
Vs=
−j
1 −j=
−j( 1 +j)
2=
√
2
2
∠−π/ 4SinceVs= 4 ∠π/4, thenVc= 2√
2 ∠ 0
so that in the steady state,vc(t)= 2√
2 cos(t)n Eigenfunction approach.Considering the output is the voltage across the capacitor and the input
is the voltage source, the transfer function is obtained using voltage division asH(s)=Vc(s)
Vs(s)=
1 /s
1 + 1 /s=
1
s+ 1so that the system frequency response at the input frequency 0 =1 isH(j 1 )=√
2
2
∠−π/ 4According to the eigenfunction property the steady-state response of the capacitor isvc(t)= 4 |H(j 1 )|cos(t+π/ 4 +∠H(j 1 ))= 2√
2 cos(t)which coincides with the solution found using phasors. nnExample 4.2
An ideal communication system provides as output the input signal with only a possible delay in
the transmission. Such an ideal system does not cause any distortion to the input signal beyond