5.6 Spectral Representation 325
The Fourier transform ofx 2 (t)=e−tu(t)is
X 2 ()=
1
1 +j
The magnitude and phase are given by
|X 2 ()|=
1
√
1 +^2
θ()=−tan−^1
When we compute these in terms of, we have
|X 2 ()| θ()
0 1 0
1
1
√
2
−π/ 4
∞ 0 −π/ 2
That is, the magnitude spectrum decays asincreases. The signalx 2 (t)is calledlow-passgiven that
the magnitude of its Fourier transform is concentrated in the low frequencies. This also implies
that the signalx 2 (t)is rather smooth. See Figure 5.7 for results. n
nExample 5.12
It is not always the case that the Fourier transform is a complex-valued function. Consider the
signals
(a)x(t)=0.5e−|t|
(b)y(t)=e−|t|cos( 0 t)
Find their Fourier transforms. Discuss the smoothness of these signals.
Solution
(a) The Fourier transform ofx(t)is
X()=
1
^2 + 1
which is a real-valued function of. Indeed,
|X()|=X() θ()
0 1 0
1 0.5 0
∞ 0 0