5.6 Spectral Representation 325The Fourier transform ofx 2 (t)=e−tu(t)isX 2 ()=
1
1 +jThe magnitude and phase are given by|X 2 ()|=
1
√
1 +^2
θ()=−tan−^1 When we compute these in terms of, we have |X 2 ()| θ()
0 1 011
√
2
−π/ 4∞ 0 −π/ 2That is, the magnitude spectrum decays asincreases. The signalx 2 (t)is calledlow-passgiven that
the magnitude of its Fourier transform is concentrated in the low frequencies. This also implies
that the signalx 2 (t)is rather smooth. See Figure 5.7 for results. nnExample 5.12
It is not always the case that the Fourier transform is a complex-valued function. Consider the
signals(a)x(t)=0.5e−|t|
(b)y(t)=e−|t|cos( 0 t)Find their Fourier transforms. Discuss the smoothness of these signals.Solution(a) The Fourier transform ofx(t)isX()=1
^2 + 1
which is a real-valued function of. Indeed, |X()|=X() θ()
0 1 0
1 0.5 0
∞ 0 0