608 C H A P T E R 10: Fourier Analysis of Discrete-Time Signals and Systems
nExample 10.17
To visualize the difference between a linear shift and a circular shift consider the periodic signal
x[n] of periodN=4 with a first periodx 1 [n]=n n=0,..., 3Plotx[−n] andx[n−1] as functions ofnusing the linear and the circular representations.SolutionIn the circular representation ofx[n], the samplesx[0],x[1],x[2], andx[3] of the first period are
located in a clockwise direction in the E(ast), S(outh), W(est), and N(orth) directions in the circle.
Considering the E direction the origin of the representation, circular shifting is done analogously
to linear shifting with respect to the origin. Delaying byMin the circular representation corre-
sponds to shifting circularly, or rotating,Mpositions in the clockwise direction. Advancing byM
corresponds to shifting circularlyMpositions in the counterclockwise direction. Reflection corre-
sponds to reversing the order of the samples ofx 1 [n] to E, N, W, and S (i.e., placing the entries of
x 1 [n] counterclockwise starting withx[0] in E).
The circular representation ofx[−n] starts withx[0] in the first quadrant and then follows withx[1],
x[2], andx[3] in a counterclockwise direction (Figure 10.11). Looking at the circular representation
in a clockwise direction we obtain the linear representation that as expected coincides with the
reflection ofx[n].FIGURE 10.11
Circular representation ofx[−n]
andx[n−1].^00
112233x[−n]n......
0
0112233x[n−1]n......x[1]x[2] x[0]x[3]x[1]x[2]x[3]x[0]