664 C H A P T E R 11: Introduction to the Design of Discrete Filters
The crossings of these lines with the filter loss function indicate that at the normalized frequency
of 0.6 the loss is 9 as desired, and that at the normalized frequency 0.47 the loss is less than 2 dB,
so that the normalized half-power frequency is about 0.5. nnExample 11.8
In this example we consider designing a Butterworth low-pass discrete filter for processing an
analog signal. The filter specifications are:fp=2250 Hz passband frequency
fst=2700 Hz stopband frequency
fs=9000 Hz sampling frequency
α 1 =−18 dB dc loss
α 2 =−15 dB loss in passband
α 3 =−9 dB loss in stopbandSolutionThe specifications are not normalized (see Figure 11.14). Normalizing them, we have that:α(ej^0 )=−18 dB
αmax=α 2 −α 1 =3 dB
αmin=α 3 −α 1 =9 dBandωp=2 πfhp
fs=0.5πωst=2 πfst
fs=0.6πNote thatωp=ωhpsince the difference in the losses at dc and atωpis 3 dB.FIGURE 11.14
Loss specifications for a discrete low-pass
filter for processing an analog signal.− 18− 15− 9f(KHz)
2 .25 2. 74. 5α(f)dB