1.3 Continuous-Time Signals 81n An analog signal x(t)is said to beabsolutely integrableif x(t)satisfies the condition
∫∞−∞|x(t)|dt<∞ (1.14)nExample 1.11
Find the energy and the power of the following:
(a) The periodic signalx(t)=cos(πt/ 2 +π/ 4 ).
(b) The complex signaly(t)=( 1 +j)ejπt/^2 , for 0≤t≤10 and zero otherwise.
(c) The pulsez(t)=1, for 0≤t≤10 and zero otherwise.Determine whether these signals are finite energy, finite power, or both.SolutionThe energy in these signals is computed as follows:Ex=∫∞
−∞cos^2 (πt/ 2 +π/ 4 )dt→∞Ey=∫^10
0|( 1 +j)ejπt/^2 |^2 dt= 2∫^10
0dt= 20Ez=∫^10
0dt= 10where we used|( 1 +j)ejπt/^2 |^2 =| 1 +j|^2 |ejπt/^2 |^2 =| 1 +j|^2 =2. Thus,x(t)is an infinite-energy sig-
nal whiley(t)andz(t)are finite-energy signals. The power ofy(t)andz(t)are zero because they
have finite energy. The power ofx(t)can be calculated by using the symmetry of the signal squared
and lettingT=NT 0 :Px=lim
T→∞2
2 T
∫T
0cos^2 (πt/ 2 +π/ 4 )dt= lim
N→∞1
NT 0
∫NT^0
0cos^2 (πt/ 2 +π/ 4 )dt= lim
N→∞1
NT 0
N
∫T^0
0cos^2 (πt/ 2 +π/ 4 )dt
=^1
T 0
∫T^0
0cos^2 (πt/ 2 +π/ 4 )dtUsing the trigonometric identitycos^2 (πt/ 2 +π/ 4 )=1
2
[cos(πt+π/ 2 )+ 1 ]