Solution
a.The system looks like this:
where the sloped line indicates the true bottom of the box.
b.In order to determine a 2 , we need to evaluate the expression
a 2
where PIAB stands for particle-in-a-box. The wavefunctions and energies for
the particle-in-a-box system are known, so all we need do is substitute for the
wavefunctions and the energies.
a 2
Since all the functions in the integral are being multiplied together, they can
be rearranged (and the constants removed from the integral sign and the
denominator simplified) to yield
a 2
In order to integrate this, we need to substitute the trigonometric identity
sin axsin bx^12 [cos (ab)xcos(ab)x] and then use the integral
table in Appendix 1. We get:
a 2
Evaluating this at the limits and simplifying, one finds that
a 2 ^1
2
2
7
8
km
(^2) h
a
2
3
and so the approximate wavefunction is
1,real 1,PIAB
1
2
2
7
8
km
(^2) h
a
2
3
2,PIAB
a
k
a^2
2 cos
a
x
a
x
sin
a
x
9
a
2
2 cos
3
a
x
3
a
x
sin
3
a
x
a 0
8
3
m
h
a
2
2
2
a
k
1
2
a
0
xcos
a
x
xcos
3
a
x
dx
8
3
m
h
a
2
2
2
a
k
a
0
xsin
2
a
x
sin
1
a
x
dx
8
3
m
h
a
2
2
a
0
2
a
sin
2
a
x
kx
2
a
sin
1
a
x
dx
8
1
m
(^2) h
a
2
2 8
2
m
(^2) h
a
2
2
a
0
*2,PIABkx1,PIABdx
E1,PIABE2,PIAB
x
12.6 Perturbation Theory 393