17.2 for an example of how to use this formula.) For a well-behaved probabil-
ity function, the summation of all probabilities,
j
Pjin the denominator,
equals 1, so equation 19.27 becomes
possible
u
values
j 1
ujPj
Finally, for a function that can have many possible values which are ex-
pressed by a smoothly varying probability function, the above summation can
be replaced with an integral, so we have
u
max
min
ujPjdu (19.28)
Equation 19.28 was derived using the same conditions describing the distrib-
ution of gas velocities. Therefore, we can use equation 19.28 to set up an inte-
gral for the average squared velocity in the xdimension. The variable is vx^2 , and
the probability function Pjis given by equation 19.24 with the subsequent de-
termination of the pre-exponential constant A. Substituting into equation
19.28, we have for the average squared velocity:
v^2 avg,x
vx^2
2
K
1/2
e(1/2)Kvx
2
dvx (19.29)
Since equation 19.29 is an even function of the variable vx, we can divide the
range in half, from 0 to rather than to , and multiply the value
of that integral by 2. Therefore,
v^2 avg,x 2
2
K
1/2
0
vx^2 e(1/2)Kvx
2
dvx (19.30)
where all constants have been removed to outside the integral. The integral in
equation 19.30 has a known form; from Appendix 1, we use 0 x^2 ebx
(^2) /2
dx
(where in equation 19.30,xvx) equals 1/2/[21/2(K)3/2]. Substituting into
equation 19.30:
v^2 avg,x 2
2
K
1/2
2 1/2(
1/
K
2
)3/2
which must equal
k
m
T
where the last part is taken from equation 19.26. Most of the terms on the K
side cancel. Solving:
1
K
k
m
T
K
k
m
T
(19.31)
We therefore have for the distribution function gx:
gx
2
m
kT
1/2
emvx
(^2) /2kT
(19.32)
Similar one-dimensional distribution functions are easily written for gyand gz.
Equation 19.32, and the two parallel functions for the yand zdimensions,
do not directly give the three-dimensional probability function. We have de-
fined the product of the three unidimensional probabilities as :
(v) gx(vx) gy(vy) gz(vz)
662 CHAPTER 19 The Kinetic Theory of Gases