9.5 Integration by parts 523
and show that multiplying the numerators and denominators of the right mem-
bers of (2) and (3) by theleft member of (4) gives the formulas
(5) or/2sin2nxdx =22nIn !2f 2
r/2 22nn!n!
sin2n+1 x dx =
1
(6) o (2n)! 2n -
One reason for interest in these things lies in the fact that the number
(2n)!
22' n!nl
is the probability of finding exactly n heads and exactly n tails when 2n coins are
tossed. Remark: We embark on a little excursion to see that these formulas
have startling consequences. When 0 < x < 2r/2, we have 0 < sin x < 1, so
(7) 0 < sin2n+l x < sin2n x < sin2n-1 x < 1
and hence
,r/2 r/2 x/2
(8) 0< fo sin2n+1 x dx < fo in2n x dx < f^0 sin2n-1 x dx.
Putting p = 2n + 1 in (1) gives the formula
(9) f
a/2 1 /2
o sin2n-1 x dx = (1 +2n/fo sin2n+1 x dx.
r
It follows from (8) and (9) that there is a number Bn for which 0 < 0n < 1 and
(10) for/2 sin 2nx dx =(1 + 2-n)
for/2
sin2n+i x dx.
:Multiplying the members of (5) and (6) gives
(11) Lfor/2 sin2n x dx ILrfor/2 sin2n+1 x dx =
4i1(1+2n!
Multiplying the members of (10) and (11) leads to the formula
/2 1 - V
(12)
for
sin2n x dx = 1
Bn
- 2n -}- 12
Substituting this in (5) gives the formula
(2n)! 1 - 0n^1
(13) 22nnln! =^1 - 2n + 1
Since 0 < On < 1, the first factor in the right member is near 1 when n islarge