680 Iterated and multiple integrals
can put these equations in the form
(13.461) x ffs S(x,y) dx dy =Ifs xS(x,y) dx dy,
y ffs S(x,y) dx dy=ffs yS(x,y)dx dy
or
IIs
xS(x,y) dx dy f f ys(x,y) dx dys
(13.462) x =
ffsS(x,y) dx dy A 3(x,y) dx dy
where the denominators are equal to the mass M of the lamina. It is
sometimes helpful to know that if, as in Figure 13.463, the line x = xo
is a line of symmetry of a homogeneous lamina, then lfI`2 = 0 and
hence x = xo In order to find the first moment MX('-', o of the lamina
about the y axis, it suffices to calculate the mass M of the lamina and
y
Figure 13.463
y
Figure 13.464
use the formula Mx = M.,('',. If, as in Figure 13.464, the lines x = xo
and y = yo are both lines of symmetry of a homogeneous lamina, then
x = xo and 5 = yo, so the centroid of the lamina is the point (xo,yo).
In case p = 2, the number M(p)g becomes
(13.47) M`2' =ffs(x - xo)25(x,y) dx dy,
the second moment or moment of inertia of the lamina about the line x = X.
When these things are being calculated and used in mechanics and else-
where, information concerning moments of inertia about parallel lines
(or axes) is very helpful. To obtain information of this nature, we let
x be the x coordinate of the centroid and use the simple identity
(x-xo)2 =[(x-x)+(x-x0)2
_ (x - g) l -F (x - xo) 2 -}- 2(9 - xo) (x - x)
to put (13.47) in the form
(13.471) M`2Z_ZQ=ffs (x- x)2S(x,y) dx dy + (x - xo)2f f, S(x,y) dx dy
- 2(9 - xo) ffs (x - z)s(x,y) dx dy.
The first term in the right member is M`2', the moment of inertiaof the