Calculus: Analytic Geometry and Calculus, with Vectors

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2.3 Scalar products, direction cosines, and lines in E3 75

Thus when we know about vectors, we can put the Newton law in the following
much more useful form. There is a constant G such that a particle P1 ofmass
ml at P1 is attracted toward a particle Pz of mass m2 at P2 by the force F defined
by (3). The problem which we originally proposed involved rectangular coordi-
nates, and it should now be completely obvious that the answer to our problem
is
(x2 - xl)1 + (Y2 - Y1)l + (z2 - zi)k
(4) F=Gmlm2[('K2 - x1)2 + (y2 - yl)2 + (z2 - z1)2]'


Remarks: Persons who work with these things normally recognize the fact that
we do not, in our physical world, have "particles" concentrated at points. It is
sometimes possible, however, to obtain useful results from calculations based on
the assumption that particles are concentrated at points. When this assumption
has been made, we can complicate ideas and simplify language by replacing the
concept of "a particle Pi at the point Pl having mass m1" by the concept of
"a point P1 having mass ml." It can be insisted that this linguistic antic should
be explained; otherwise, a serious student of mathematics is entitled to ask where
the postulates of Euclid provide for the possibility that some points can be
heavier than others. Finally, it can be insisted that the formulas (3) and (4)
should not be remembered; it is better to know (2) and to understand the very
simple process by which we use it to obtain the more useful formulas (3) and (4)
whenever we want them.
20 Let Pi(xl,yl,zi) and P2(x2,y2,z2) be two distinct points in E3 and recall
(or prove again) that to each point P(x,y,z) on the line L containing Pl and P2
there corresponds a number X for which
(1) x = x1 + n(x2 - xl), Y = Y2 + X(Y2 - yl), z = z2 + n(z2 - zl)-

While we may not yet know why such matters are important, we can observe
that the equations
x' = a11x + any + a13z + b1
(2) y' = a21x + a22y + a23z + b2
z' = a31x + a32Y + a33z + b3,

in which the a's and b's are constants, provide mathematical machinery into
which we can substitute the coordinates (x,y,z) of a point in E3 and thereby obtain
the coordinates (x',y',z') of a point (usually another point) in E3. It is very
helpful to think of the equations (2) as being a transformer which transforms a
given point P(x,y,z) into a transform (or transformed point) P'(x',y',z'). Thus
the transformer goes to work on P(x,y,z), which engineers and others call an
input, and produces P'(x',y',z'), which they call an output. This problem con-
cerns transforms of points that lie on the given line L. Find, for each X, the
transform P'(x',y',z') of the point P(x,y,z) on L whose coordinates are given by
(1). .dns.: The result can be put in the form

x' = x1 + X(x2 - x1), y' = A + X(Y2 - A), z' = zi + X(z2 - a1),
where
xk = alixk + a12yk + a13zk + b2
Yk = a21xk + a22yk + a23zk + bx
zk = a31xk + a32yk + a33zk + b3
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