(
γμ
∂
∂xμ
+
mc
̄h
)
ψ= 0
Thisgives us the Dirac equationindicating that this Lagrangian is the right one. The Euler-
Lagrange equation derived using the fieldsψis theDirac adjoint equation,
∂
∂xμ
(
∂L
∂(∂ψ/∂xμ)
)
−
∂L
∂ψ
= 0
∂
∂xμ
(
−c ̄hψγ ̄μ
)
+mc^2 ψ ̄ = 0
−
∂
∂xμ
ψγ ̄μ+mc
̄h
ψ ̄ = 0
again indicating that this is thecorrect Lagrangian if the Dirac equation is assumed to be
correct.
To compute theHamiltonian density, we start by finding the momenta conjugate to the fieldsψ.
Π =
∂L
∂
(
∂ψ
∂t
)=−c ̄hψγ ̄ 4
1
ic
=i ̄hψ†γ 4 γ 4 =i ̄hψ†
There is no time derivative ofψ ̄so those momenta are zero. The Hamiltonian can then be computed.
H =
∂ψ
∂t
Π−L
= i ̄hψ†
∂ψ
∂t
+c ̄hψγ ̄μ
∂
∂xμ
ψ+mc^2 ψψ ̄
= −c ̄hψ†
∂ψ
∂x 4
+c ̄hψ†γ 4 γ 4
∂ψ
∂x 4
+c ̄hψγ ̄k
∂
∂xk
ψ+mc^2 ψψ ̄
= ̄hcψ†γ 4 γk
∂
∂xk
ψ+mc^2 ψ†γ 4 ψ
= ψ†
(
̄hcγ 4 γk
∂
∂xk
ψ+mc^2 γ 4
)
ψ
H =
∫
ψ†
(
̄hcγ 4 γk
∂
∂xk
+mc^2 γ 4
)
ψd^3 x
We may expand the fieldψin thecomplete set of plane waveseither using the four spinorsu
(r)
~p
forr= 1, 2 , 3 ,4 or using the electron and positron spinorsu
(r)
~p andv
(r)
~p forr= 1,2. For economy of
notation, we choose the former with a plan to change to the later once the quantization is completed.
ψ(~x,t) =
∑
~p
∑^4
r=1
√
mc^2
|E|V
c~p,ru(~pr)ei(~p·~x−Et)/ ̄h
The conjugate can also be written out.
ψ†(~x,t) =
∑
~p
∑^4
r=1
√
mc^2
|E|V
c∗~p,ru(~pr)†e−i(~p·~x−Et)/ ̄h