5.56 I FUNDAMENTALS OF BUSINESS MATHEMATICS AND STATISTICSMeasures of Central Tendency and Measures of Dispersion
Solution :
Table : Calculation of Standard Deviationx f d d′= 10 d fd¢ fd¢^2
4.5 2 –30 –3 –6 18
14.5 3 –20 –2 –6 12
24.5 5 –10 –1 –5 5
34.5 17 0 0 0 0
44.5 12 10 1 12 12
54.5 7 20 2 14 28
64.5 4 30 3 12 36
∑f 50= – – ∑fd′=^21 ∑fd′^2 =^111fd^2 fd^22
i^1112110
f f 50 50 ′ ′
σ = − × = − ×
∑ ∑
∑ ∑= (2.22 0.1764− )× 10 = 1.4295 × 10 = 14.295.(C) For Continuous Series (or group distribution) : Any method discussed above (for discrete series) can be
used in this case. Of course, step deviation method is convenient to use. From the following example,
procedure of calculation will be clear.
Example 53 : Find the standard deviation from the following frequency distribution.Weight (kg.) No. of persons
44–46 3
46–48 24
48–50 27
50–52 21
52–-54 5
Total 80