FUNDAMENTALS OF BUSINESS MATHEMATICS AND STATISTICS I 5.59
Solution :
(a) For firm A : total wages = 586 × 52.5 = 30,765. For firm B : Total wages = 648 × 47.5 =
30,780. i.e. Firm B pays largest amount.
(b) For firm A : σ^2 = 100 ∴ σ = 10
Now, v=Meanσ ×^100 =52.5^10 ×100 19.04=
For firm B : σ^2 = 121 ∴ σ = 11
V^11 100 23.16
=47.5× =
∴ Firm B has greater variability, as its coefficient of variation is greater than that of Firm A.
(c) Here, n 1 = 586, x 1 =52.5,σ = 1 10
n 2 =648, x 2 =47.5σ = 2 11
12 1 1 2 2
1 2
x n x n x 586 52.5 648 47.5 30,765 30,780
n n 586 648 1234
∴ = + = × + × = +
+ +
6 1,545 49.87
=1,234 = = ` 49.9
Again, d 1 =x 1 −x 2 =52.5 49.9 2.6 ;− = d 2 = 47.5 – 49.9 = – 2.4
1 1^2 2 2^2 1 1^2 2 2^2
(^1212)
n n n d n d
n n
∴ σ = σ + σ + +
+
586 10( )^2 648 11( )^2 586 2.6( )^2 648 2.4( )^2
586 648
+ + + −
= +
58600 78408 3962 3733
1234
= + + +
144703
1234
= = 10.83 (Calculation by log table)
Example 57 : In an examination a candidate scores the following percentage of marks :
English 2nd language mathematics Science Economics
62 74 58 61 44
Find the candidates weighted mean percentage weighted of 3, 4, 4, 5 and 2 respectively are allotted of
the subject. Find also the coefficient of variation.