10.18 I FUNDAMENTALS OF BUSINESS MATHEMATICS AND STATISTICS
Theoretical Distribution
Solution:
Fitting Poisson Distribution
No. of Defective No. of Sets fx
0790
11818
224
313
400
N = 100 ∑=fx 25
.25
(1) (0)
(2) (1)
(3) (2)
(4) (3)
(^25) 0.25
100
0.779 (Given)
(0) 100 0.779 77.90
1 77.9 0.25 19.48
19.48 0.25 2.44
22
2.44 0.25 0.20
33
0.20 0.25 0.01
44
m
X
e
NP Ne
NP NP m
NP NP m
NP NP m
NP NP m
−
−
==
=
==×=
=×=×=
=×= ×=
=×=×=
=×=×=
Example 20 :
Fit a Poisson Distribution to the following data and calculate the theoretical frequencies :
x:01234
f: 123 59 14 3 1
Solution :
x01234
f (^123591431) ∑=f 200
fx 0 59 28 9 4 ∑=fx 100
Mean =^100200
= 0.5
NP(o) = Ne–m
= 200 ×e–5
= 200 ×.6065 = 121.3