QuantumPhysics.dvi

(Wang) #1

The operatorH 1 will be self-adjoint if a domainD(H 1 ) can be chosen for the functionsψ


andφsuch thatj(0) = 0 forany pairψ,φ∈ D(H 1 ). This will be the case if the domain is


defined to be the subspace ofC∞functions which obey


ψ(0) +λ



dx


(0) = 0 (5.121)


for a given real constantλ. Note thatλ= 0 and corresponds to Dirichlet boundary condi-


tions, whileλ=∞corresponds to Neumann boundary conditions. Thus,λparametrizes an


interpolation between Dirichlet and Neumann boundary conditions, and for each value ofλ,


H 1 is self-adjoint.


The spectrum ofH 1 depends onλeven though, at face value, the differential operatorH 1


of (5.118) does not involveλ. Consider, for example, the problem with a potentialV(x) = 0


for 0≤x < ℓ, andV(x) = +∞forx≥ℓ, and solve for the eigenvaluesEofH 1. To satisfy


the vanishing boundary condition atx=ℓ, we must have


ψ(x) = sink(x−ℓ) E=


̄h^2 k^2


2 m


(5.122)


wherekcan be any positive real number. Enforcing also theλ-dependent boundary condition


(5.121) atx= 0 renders the spectrum ofkdiscrete, and requires,


tg(kℓ) =λk (5.123)


We recover the special cases,


λ= 0 kn=


2 nπ


2 ℓ


n= 1, 2 , 3 ,···


λ=∞ kn=


(2n−1)π


2 ℓ


(5.124)


For intermediate values ofλ, the solutions are transcendental, and may be determined graph-


ically. They clearly interpolate between the above cases. Thus, thespectrum depends on


the precise domain, through the boundary conditions.


5.9.2 Example 2: One-dimensional momentum in a box


Next, consider the 1-dim quantum system given by the Hamiltonian,


H 2 =i ̄hc


d


dx


(5.125)


As an operator on functions on the real line,H 2 is self-adjoint. But what happens when we


attempt to put the system in a box? For example, canH 2 be self-adjoint when acting on


functions on the finite interval [0,ℓ] withℓ >0?

Free download pdf