FIRST LAW OF THERMODYNAMICS 111
dharm
M-therm/th4-1.pm5
= (u 2 + pv 2 ) – (u 1 + pv 1 ) = h 2 – h 1 [Q h = u + pv]
or Q = h 2 – h 1 = cp (T 2 – T 1 ) ...(4.28)
where h = Enthalpy (specific), and
cp = Specific heat at constant pressure.
For mass, m, of working substance
Q = H 2 – H 1 = mcp (T 2 – T 1 ) ...[4.28 (a)]
[Q mh = H]
- Reversible Temperature (or Isothermal) Process (pv = constant, T = constant) :
A process at a constant temperature is called an isothermal process. When a working
substance in a cylinder behind a piston expands from a high pressure to a low pressure there is a
tendency for the temperature to fall. In an isothermal expansion heat must be added continuously
in order to keep the temperature at the initial value. Similarly in an isothermal compression heat
must be removed from the working substance continuously during the process.
Fig. 4.7 shows the system and states before and after the heat addition at constant
temperature.
Gas
(a) (b)
Piston
Heat source
Constant temperature
process (p.v = constant)
2
v 1 v 2
p 2
p 1
p
1
v
Fig. 4.7. Reversible isothermal process.
Considering unit mass of working substance and applying first law to the process
Q = (u 2 – u 1 ) + W
= cv (T 2 – T 1 ) + W
= 0 + W [Q T 2 = T 1 ]
The work done, W = pdv
1
2
z
In this case pv = constant or p=Cv (where C = constant)
∴ WCdv
v
CvCv
v v
v
e v
v
==z =e
1
2
1
2 2
1
log log